python - Regex: Why do empty strings get included (in a list of tuples) in re.findall()?

Question

According to the pattern match here, the matches are 213.239.250.131 and 014.10.26.06.

Yet when I run the generated Python code and print out the value of re.findall(p, test_str), I get:

[('', '', '213.239.250.131'), ('', '', '014.10.26.06')]

I could hack around the list and it tuples to get the values I'm looking for (the IP addresses), but (i) they might not always be in the same position in the tuples and (ii) I'd rather understand what's going on here so I can either tighten up the regex, or extract only IP addresses using Python's own re functionality.

Why do I get this list of tuples, why the apparent whitespace matches, and how do we ensure that only the IP addresses are returned?

Answer 1

Whenever you are using a capturing group, it always returns a submatch, even if it is empty/null. You have 3 capturing groups, so you will always have them in the findall result.

In regex101.com, you can see these non-participating groups by turning them on in Options:

You may tighten up your regex by removing capturing groups:

(?:[a-z0-9]{1,4}:+){3,5}[a-z0-9]{1,4}|d{1,3}.d{1,3}.d{1,3}.d{1,3}

Or even (?:[a-z0-9]{1,4}:+){3,5}[a-z0-9]{1,4}|d{1,3}(?:.d{1,3}){3}.

See a regex demo

And since the regex pattern does not contain capturing groups, re.findall will only return matches, not capturing group contents:

import re
p = re.compile(r'(?:[a-z0-9]{1,4}:+){3,5}[a-z0-9]{1,4}|d{1,3}.d{1,3}.d{1,3}.d{1,3}')
test_str = "from mail.example.com (example.com. [213.239.250.131]) by
 mx.google.com with ESMTPS id xc4si15480310lbb.82.2014.10.26.06.16.58 for
 <alex@example.com> (version=TLSv1.2 cipher=ECDHE-RSA-AES128-GCM-SHA256
 bits=128/128); Sun, 26 Oct 2014 06:16:58 -0700 (PDT)"
print(re.findall(p, test_str))

Output of the online Python demo:

['213.239.250.131', '014.10.26.06']