Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
537 views
in Technique[技术] by (71.8m points)

php - mySQL query returning Resource id #5

I've searched about possible solutions to this. and I've tried looping as well as trying the variants of mysql_fetch_assoc and mysql_fetch_array but I'm still getting the Resource id #5: 0: error.

Here's my code which I think generates the error.

   <?php
            mysqlc();
            $email = GetSQLValueString($_SESSION['user'], "text");
            $query = sprintf("SELECT * FROM newmember WHERE email = %s",$email);
            $res = mysql_query($query) or die('Query failed: ' . mysql_error() . "<br />
$sql");
            $row = mysql_fetch_assoc($res);
    ?>  
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Please use this one :

 while($row = mysql_fetch_object($res)){

              //do somthing 
              echo $row->name;

        }

I am already use this one in our code


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...