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in Technique[技术] by (71.8m points)

php - mySQL query returning Resource id #5

I've searched about possible solutions to this. and I've tried looping as well as trying the variants of mysql_fetch_assoc and mysql_fetch_array but I'm still getting the Resource id #5: 0: error.

Here's my code which I think generates the error.

   <?php
            mysqlc();
            $email = GetSQLValueString($_SESSION['user'], "text");
            $query = sprintf("SELECT * FROM newmember WHERE email = %s",$email);
            $res = mysql_query($query) or die('Query failed: ' . mysql_error() . "<br />
$sql");
            $row = mysql_fetch_assoc($res);
    ?>  
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Welcome To Ask or Share your Answers For Others

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by (71.8m points)

Please use this one :

 while($row = mysql_fetch_object($res)){

              //do somthing 
              echo $row->name;

        }

I am already use this one in our code


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