python - Create a 2D array from another array and its indices with NumPy

Question

Given an array:

arr = np.array([[1, 3, 7], [4, 9, 8]]); arr

array([[1, 3, 7],
       [4, 9, 8]])

And given its indices:

np.indices(arr.shape)

array([[[0, 0, 0],
        [1, 1, 1]],

       [[0, 1, 2],
        [0, 1, 2]]])

How would I be able to stack them neatly one against the other to form a new 2D array? This is what I'd like:

array([[0, 0, 1],
       [0, 1, 3],
       [0, 2, 7],
       [1, 0, 4],
       [1, 1, 9],
       [1, 2, 8]])

This is my current solution:

def foo(arr):
    return np.hstack((np.indices(arr.shape).reshape(2, arr.size).T, arr.reshape(-1, 1)))

It works, but is there something shorter/more elegant to carry this operation out?

Answer 1

Using array-initialization and then broadcasted-assignment for assigning indices and the array values in subsequent steps -

def indices_merged_arr(arr):
    m,n = arr.shape
    I,J = np.ogrid[:m,:n]
    out = np.empty((m,n,3), dtype=arr.dtype)
    out[...,0] = I
    out[...,1] = J
    out[...,2] = arr
    out.shape = (-1,3)
    return out

Note that we are avoiding the use of np.indices(arr.shape), which could have slowed things down.

Sample run -

In [10]: arr = np.array([[1, 3, 7], [4, 9, 8]])

In [11]: indices_merged_arr(arr)
Out[11]: 
array([[0, 0, 1],
       [0, 1, 3],
       [0, 2, 7],
       [1, 0, 4],
       [1, 1, 9],
       [1, 2, 8]])

---

Performance

arr = np.random.randn(100000, 2)

%timeit df = pd.DataFrame(np.hstack((np.indices(arr.shape).reshape(2, arr.size).T,
                                arr.reshape(-1, 1))), columns=['x', 'y', 'value'])
100 loops, best of 3: 4.97 ms per loop

%timeit pd.DataFrame(indices_merged_arr_divakar(arr), columns=['x', 'y', 'value'])
100 loops, best of 3: 3.82 ms per loop

%timeit pd.DataFrame(indices_merged_arr_eric(arr), columns=['x', 'y', 'value'], dtype=np.float32)
100 loops, best of 3: 5.59 ms per loop

Note: Timings include conversion to pandas dataframe, that is the eventual use case for this solution.