python - How to print a message, when error message is displayed on website selenium

Question

Hi I am trying to scrape a website using selenium after sometime the website blocks my ip for scraping and a pop up message appears.

What i want to do is that whenever that pop up message appear it displays a warning on my terminal, My code looks like this to get the result

blo = driver.find_element_by_xpath('/html/body/div[2]/div/div/div[1]/h3')
if blo:
    print('ip blocked')
else:
    print('eroor')

But its not working i just get a blank screen, How can i solve this

HTML of the element:

<h3 class="modal-title">Notifications</h3>
<div class="alert alert-warning">Sorry, you have exceeded the maximum number of queries allowed per day. If you believe you have reached this message in error, please contact our support team.</div>

Answer 1

The validate the presence of the pop up message you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

• Using CSS_SELECTOR:

  try:
      WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "h3.modal-title+div.alert.alert-warning")))
      print("ip blocked")
  except TimeoutException:
      print("eroor")
  

• Using XPATH:

  try:
      WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//h3[@class='modal-title' and text()='Notifications']//following::div[@class='alert alert-warning']")))
      print("ip blocked")
  except TimeoutException:
      print("eroor")