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pyspider 如何获取某个列表中的第n个元素

response.doc('.link_nei>ul>li>a').items()
上面的语句是用来获取所有符合条件的 <a>,我想获得倒数第二个 <a> 应该怎么获得? 教程上都是通过正则表达式去筛选,不过这种方法好 low 而且不实用


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response.doc('.link_nei>ul>li>a').eq(-2).items()

参考 pyquery 的文档 https://pythonhosted.org/pyqu...


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