python's re: return True if string contains regex pattern

Question

I have a regular expression like this:

regexp = u'ba[r|z|d]'

Function must return True if word contains bar, baz or bad. In short, I need regexp analog for Python's

'any-string' in 'text'

How can I realize it? Thanks!

Answer 1

import re
word = 'fubar'
regexp = re.compile(r'ba[rzd]')
if regexp.search(word):
  print 'matched'