python - How to retrieve minimum unique values from list?

Question

I have a list of dictionary. I wish to have only one result for each unique api and the result need to show according to priority: 0, 1, 2. May I know how should I work on it?

Data:

[
{'api':'test1', 'result': 0},
{'api':'test2', 'result': 1},
{'api':'test3', 'result': 2},
{'api':'test3', 'result': 0},
{'api':'test3', 'result': 1},
]

Expected output:

[
{'api':'test1', 'result': 0},
{'api':'test2', 'result': 1},
{'api':'test3', 'result': 0},
]

Answer 1

data = [
    {'api': 'test1', 'result': 0},
    {'api': 'test3', 'result': 2},
    {'api': 'test2', 'result': 1},
    {'api': 'test3', 'result': 1},
    {'api': 'test3', 'result': 0}
]

def find(data):
    step1 = sorted(data, key=lambda k: k['result'])
    print('step1', step1)

    step2 = {}
    for each in step1:
        if each['api'] not in step2:
            step2[each['api']] = each
    print('step2', step2)

    step3 = list(step2.values())
    print('step3', step3)
    print('
')
    return step3

find(data)

Try this, it will give you

step1 [{'api': 'test1', 'result': 0}, {'api': 'test3', 'result': 0}, {'api': 'test2', 'result': 1}, {'api': 'test3', 'result': 1}, {'api': 'test3', 'result': 2}]
step2 {'test1': {'api': 'test1', 'result': 0}, 'test3': {'api': 'test3', 'result': 0}, 'test2': {'api': 'test2', 'result': 1}}
step3 [{'api': 'test1', 'result': 0}, {'api': 'test3', 'result': 0}, {'api': 'test2', 'result': 1}]

Sort all first, then find first for each "api", and there goes your result.