Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
239 views
in Technique[技术] by (71.8m points)

php - How do I implement Direct Identity based OpenID authentication with Zend OpenID

I'm using the Zend framework and the openid selector from http://code.google.com/p/openid-selector/ - however I find I can't login using sites like Google and Yahoo as they use direct identity based login system whereby one is just redirected to a url as opposed to entering a unique url of their own for authentication.

I've checked out many options and hacks but none of them seem to work. How can i get this to work here btw - how is it implemented at stack overflow? I could really use all the help here guys..


Edit

Well the issue here is that from what I have noticed is that the Zend OpenID class doesn't support OpenID 2.0 the thing is that a typical open ID providor gives you a unique url such as your-name.openid-providor.com or openid-providor.com/your-name and the Zend OpenId class just parses through that url and then redirects you to the providor website where upon authentication you are redirected back.

In the case of Yahoo and google - you don't enter a unique url instead you are redirected to the providors login site and upon login and authentication you are redirected back - so basically whats happeining is that the zend_openID object when it parses to tell who the providor is it fails to tell from the general url itself. Like when you click on teh Google link it redirects you to https://www.google.com/accounts/o8/id

Its more an issue with the zend openid object here and there isn't any help on zend related forums - so I was wondering if someone had already hacked or had an alteration I could make to the class to accomplish this. Sorry if I'm missing something but I'm kinda new to this and programming with open ID and have just started to get my feet wet.


Thanks for the follow up - I did check into RPX a while back and they do have a php class but I wasnt able to check it out plus I really just want to for now get the code selector used as on stackoverflow to work with Yahoo and Google authentication. There has to be some kind of way to tweak the parsing which the Zend OpenID class uses as it runs a series of regular expression checks to make a discovery.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Little late to the game but I was able to get this working with some hacks I found around the interwebs.

First. Yahoo. To get Yahoo working all I had to do was change the JavaScript to use me.yahoo.com instead of just yahoo.com and it worked perfectly with the version of the Zend Framework I'm using. Unfortunately Google still wasn't, so some hacking was in order.

All of these changes go in Zend/OpenId/Consumer.php

First, in the _discovery method add the following on the series of preg_match checks that starts at around line 740.

} else if (preg_match('/<URI>([^<]+)</URI>/i', $response, $r)) {
    $version = 2.0;
    $server = $r[1];

I added this right before the return false; statement that's in the else {} block.

Second, in the _checkId method you'll need to add 3 new blocks (I haven't dug around enough to know what causes each of these three cases to be called, so I covered all to be on the safe side.

Inside the $version <= 2.0 block, you'll find an if/else if/else block. In the first if statement ($this->_session !== null) add this to the end:

if ($server == 'https://www.google.com/accounts/o8/ud') {
    $this->_session->identity = 'http://specs.openid.net/auth/2.0/identifier_select';
    $this->_session->claimed_id = 'http://specs.openid.net/auth/2.0/identifier_select';
}

In the else if (defined('SID') block add this to the end:

if ($server == 'https://www.google.com/accounts/o8/ud') {
    $_SESSION['zend_openid']['identity'] = 'http://specs.openid.net/auth/2.0/identifier_select';
    $_SESSION['zend_openid']['claimed_id'] = 'http://specs.openid.net/auth/2.0/identifier_select';
}

And then after the else block (so outside the if/else if/else block all together, but still inside the $version <= 2.0 block) add this:

if ($server == 'https://www.google.com/accounts/o8/ud') {
    $params['openid.identity'] = 'http://specs.openid.net/auth/2.0/identifier_select';
    $params['openid.claimed_id'] = 'http://specs.openid.net/auth/2.0/identifier_select';
}

Link to the bug in Zend Framework Issue Tracker


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...