numpy - Is there a Python equivalent of range(n) for multidimensional ranges?

Question

On Python, range(3) will return [0,1,2]. Is there an equivalent for multidimensional ranges?

range((3,2)) # [(0,0),(0,1),(1,0),(1,1),(2,0),(2,1)]

So, for example, looping though the tiles of a rectangular area on a tile-based game could be written as:

for x,y in range((3,2)):

Note I'm not asking for an implementation. I would like to know if this is a recognized pattern and if there is a built-in function on Python or it's standard/common libraries.

Answer 1

In numpy, it's numpy.ndindex. Also have a look at numpy.ndenumerate.

E.g.

import numpy as np
for x, y in np.ndindex((3,2)):
    print(x, y)

This yields:

0 0
0 1
1 0
1 1
2 0
2 1