Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
512 views
in Technique[技术] by (71.8m points)

sql - mysql recursive(tree) parent child category

I am new in mysql. This is my table:

category table:

id | name        | prent
----------------------------
1  |  os         | null
2  | linux       | 1
3  | ubuntu      | 2
4  | xubuntu     | 3
5  | lubuntu     | 3
6  | zubuntu     | 3
7  | zubuntu 2   | 6
8  | suse        | 2
9  | fedora      | 2
10 | windowse    | 1
11 | windowse xp | 10
12 | windowse 7  | 10
13 | windowse 8  | 10
14 | food        | null
15 | dance       | null

Each category has a parent and I want to prepare them to show in a drop-down menu.

This is what I want to get:

id | name          | depth
----------------------------
1  | os            | 0
2  | -linux        | 1
3  | --ubuntu      | 2
4  | ---xubuntu    | 3
5  | ---lubuntu    | 3
6  | ---zubuntu    | 3
7  | ----zubuntu 2 | 4
8  | --suse        | 2
9  | --fedora      | 2
10 | -windows      | 1
11 | --windows  xp | 2
12 | --windows  7  | 2
13 | --windows  8  | 2
14 | food          | 0
15 | dance         | 0

Here, categories are not in order and my code has to provide order for children categories far from their parents. Indentation before name is provided based on depth of parents of each category. There is no limit for number of children of each category however the total number of categories will not exceed 100.

Is there any query that gives such result? I prefer a query that can be run in form of active record in a PHP framework.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

This Thread led me. Thanks to @RolandoMySQLDBA

DELIMITER $$
DROP FUNCTION IF EXISTS `GetAncestry` $$
CREATE FUNCTION `GetAncestry` (GivenID INT) RETURNS VARCHAR(1024)
DETERMINISTIC
BEGIN
    DECLARE rv VARCHAR(1024);
    DECLARE cm CHAR(1);
    DECLARE ch INT;

    SET rv = '';
    SET cm = '';
    SET ch = GivenID;
    WHILE ch > 0 DO
        SELECT IFNULL(`prent`,-1) INTO ch FROM
        (SELECT `prent` FROM Table1 WHERE id = ch) A;
        IF ch > 0 THEN
            SET rv = CONCAT(rv,cm,ch);
            SET cm = ',';
        END IF;
    END WHILE;
    RETURN rv;

END $$
DELIMITER ;

A working fiddle here.

SELECT id,GetAncestry(id) as parents from Table1 where id = 7;

ID  PARENTS
7   6,3,2,1

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...