Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
966 views
in Technique[技术] by (71.8m points)

regex - Java function to return if string contains illegal characters

I have the following characters that I would like to be considered "illegal":

~, #, @, *, +, %, {, }, <, >, [, ], |, , , , _, ^

I'd like to write a method that inspects a string and determines (true/false) if that string contains these illegals:

public boolean containsIllegals(String toExamine) {
    return toExamine.matches("^.*[~#@*+%{}<>[]|"\_^].*$");
}

However, a simple matches(...) check isn't feasible for this. I need the method to scan every character in the string and make sure it's not one of these characters. Of course, I could do something horrible like:

public boolean containsIllegals(String toExamine) {
    for(int i = 0; i < toExamine.length(); i++) {
        char c = toExamine.charAt(i);

        if(c == '~')
            return true;
        else if(c == '#')
            return true;

        // etc...
    }
}

Is there a more elegant/efficient way of accomplishing this?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can make use of Pattern and Matcher class here. You can put all the filtered character in a character class, and use Matcher#find() method to check whether your pattern is available in string or not.

You can do it like this: -

public boolean containsIllegals(String toExamine) {
    Pattern pattern = Pattern.compile("[~#@*+%{}<>\[\]|"\_^]");
    Matcher matcher = pattern.matcher(toExamine);
    return matcher.find();
}

find() method will return true, if the given pattern is found in the string, even once.


Another way that has not yet been pointed out is using String#split(regex). We can split the string on the given pattern, and check the length of the array. If length is 1, then the pattern was not in the string.

public boolean containsIllegals(String toExamine) {
    String[] arr = toExamine.split("[~#@*+%{}<>\[\]|"\_^]", 2);
    return arr.length > 1;
}

If arr.length > 1, that means the string contained one of the character in the pattern, that is why it was splitted. I have passed limit = 2 as second parameter to split, because we are ok with just single split.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...