Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
270 views
in Technique[技术] by (71.8m points)

python - Numpy: Check if float array contains whole numbers

In Python, it is possible to check if a float contains an integer value using n.is_integer(), based on this QA: How to check if a float value is a whole number.

Does numpy have a similar operation that can be applied to arrays? Something that would allow the following:

>>> x = np.array([1.0 2.1 3.0 3.9])
>>> mask = np.is_integer(x)
>>> mask
array([True, False, True, False], dtype=bool)

It is possible to do something like

>>> mask = (x == np.floor(x))

or

>>> mask = (x == np.round(x))

but they involve calling extra methods and creating a bunch of temp arrays that could be potentially avoided.

Does numpy have a vectorized function that checks for fractional parts of floats in a way similar to Python's float.is_integer?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

From what I can tell, there is no such function that returns a boolean array indicating whether floats have a fractional part or not. The closest I can find is np.modf which returns the fractional and integer parts, but that creates two float arrays (at least temporarily), so it might not be best memory-wise.

If you're happy working in place, you can try something like:

>>> np.mod(x, 1, out=x)
>>> mask = (x == 0)

This should save memory versus using round or floor (where you have to keep x around), but of course you lose the original x.

The other option is to ask for it to be implemented in Numpy, or implement it yourself.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...