Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
255 views
in Technique[技术] by (71.8m points)

python key in dict.keys() performance for large dictionaries

I was wondering if you guys might be able to give me some advice in regards to making the performance of my code much better.

I have a set of for loops which look to see if a key is in a dictionary of which its values are a list, if the key exists, it appends to the list and if it doesnt it adds a new list in for that key

dict={}
for value in value_list:
   if value.key in dict.keys():
      temp_list = dict[value.key]
      temp_list.append(value.val)
      dict[value.key] = temp_list
   else:
      dict[value.key] = [value.val]

Now this code works fine, but evenrually as the dictionary starts to fill up the line value.key in dict.keys() becomes more and more cumbersome.

Is there a better way of doing this?

Thanks,

Mike

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Don't do this:

value.key in dict.keys()

That--in Python 2, at least--creates a list containing every key. That gets more and more expensive as the dictionary gets larger, and performs an O(n) search on the list to find the key, which defeats the purpose of using a dict.

Instead, just do:

value.key in dict

which doesn't create a temporary list, and does a hash table lookup for the key rather than a linear search.

setdefault, as mentioned elsewhere, is the cleaner way to do this, but it's very important to understand the above.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...