Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
528 views
in Technique[技术] by (71.8m points)

makefile - How to make a failing $(shell) command interrupt Make

I have a Makefile that starts by running a tool before applying the build rules (which this tool writes for me). If this tool, which is a python script, exits with a non-null status code, I want GNU Make to stop right there and not go on with building the program.

Currently, I do something like this (top level, i.e. column 1):

$(info Generating build rules...)
$(shell python collect_sources.py)
include BuildRules.mk

But this does not stop make if collect_sources.py exits with a status code of 1. This also captures the standard output of collect_sources.py but does not print it out, so I have the feeling I'm looking in the wrong direction.

If at all possible, the solution should even work when a simple MS-DOS shell is the standard system shell.

Any suggestion?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

There might be a better way, but I tried the following and it works:

$(if $(shell if your_command; then echo ok; fi), , $(error your_command failed))

Here I did assume that your_command does not give any output, but it shouldn't be hard to work around such a situation.

Edit: To make it work with the default Windows shell (and probably any decent shell) you could write your_command && echo ok instead of the if within the shell function. I do not think this is possible for (older) DOS shells. For these you probably want to adapt your_command or write a wrapper script to print something on error (or success).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...