I've seen plenty of posts all around about this... but I can not, for the life of me, figure out what my problem is! Google Chrome just displays a blank page when I try to transform XML with XSL. When I view source, I see the raw XML. IE works.
I have an XML document that looks like this...
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="http://localhost/xsl/listXSL.php"?>
<links>
<link id="1" name="Google Home Page" url="http://www.google.com/" clicks="0" />
<link id="2" name="Facebook" url="http://www.facebook.com/" clicks="1" />
<link id="3" name="Gmail" url="http://gmail.com" clicks="2" />
</links>
... and then the linked XSL file which looks like this...
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="links/link">
<a>
<xsl:attribute name="href">
<xsl:value-of select="@url" />
</xsl:attribute>
<xsl:value-of select="@name" />
</a><br />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
You might notice that the XSL file is actually a PHP file, but this works fine in other browsers and I've tried changing it to .xsl for Chrome, but it doesn't help. What I'm doing wrong here?
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