inheritance - Extend Javascript promise and resolve or reject it inside constructor

Question

I want to extend native Javascript Promise class with ES6 syntax, and be able to call some asynchronous function inside the subclass constructor. Based on async function result the promise must be either rejected or resolved.

However, two strange things happen when then function is called:

1. subclass constructor is executed twice
2. "Uncaught TypeError: Promise resolve or reject function is not callable" error is thrown

    class MyPromise extends Promise {
        constructor(name) {
            super((resolve, reject) => {
                setTimeout(() => {
                    resolve(1)
                }, 1000)
            })

            this.name = name
        }
    }

    new MyPromise('p1')
        .then(result => {
            console.log('resolved, result: ', result)
        })
        .catch(err => {
            console.error('err: ', err)
        })

Answer 1

The reasoning is simple but not necessarily self evident.

• .then() returns a promise
• if then is called on a subclass of Promise, the returned promise is an instance of the subclass, not Promise itself.
• the then returned promise is constructed by calling the subclass constructor, and passing it an internal executor function that records the value of resolve and reject arguments passed to it for later use.
• "later use" covers resolving or rejecting the promise returned by then asynchronously when monitoring execution of onfulfilled or onrejected handlers (later) to see if they return a value (which resolves the then returned promise) or throw an error (which rejects the promise).

In short then calls internally obtain and record references to the resolve and reject functions of promises they return.

---

So regarding the question,

new MyPromise( 'p1')

works fine and is the first call to the subclass constructor.

.then( someFunction)

records someFunction in a list of then calls made on new MyPromise (recall then can be called multiple times) and attempts to create a return promise by calling

new MyPromise( (resolve, reject) => ... /* store resolve reject references */

This is the second call to the subclass constructor coming from then code. The constructor is expected to (and does) return synchronously.

On return from creating the promise to return, the .then method makes an integrity check to see if the resolve and reject functions it needs for later use are in fact functions. They should have been stored (in a list) along with callbacks provided in the then call.

In the case of MyPromise they are not. The executor passed by then, to MyPromise, is not even called. So then method code throws a type error "Promise resolve or reject function is not callable" - it has no means of resolving or rejecting the promise it is supposed to return.

When creating a subclass of Promise, the subclass constructor must take an executor function as its first argument, and call the executor with real resolve and reject functional arguments. This is internally required by then method code.

Doing something intricate with MyPromise, perhaps checking the first parameter to see if it is a function and calling it as an executor if it is, may be feasible but is outside the scope of this answer! For the code shown, writing a factory/library function may be simpler:

function namedDelay(name, delay=1000, value=1) {
     var promise = new Promise( (resolve,reject) => {
         setTimeout(() => {
                resolve(value)
            }, delay)
         }
     );
    promise.name = name;
    return promise;
}

namedDelay( 'p1')
    .then(result => {
        console.log('fulfilled, result: ', result)
    })
    .catch(err => {
        console.error('err: ', err)
    })