python - how to catch specific pyodbc error message

Question

I trid the following code,

import pyodbc
try:
    pyodbc.connect('DRIVER={%s};SERVER=%s;DATABASE=%s;UID=%s;PWD=%s' % (driver, server, database, uid, password))
except pyodbc.Error, err:
    logging.warn(err)

The error message format i get is

('HY000', "[HY000] [MySQL][ODBC 5.1 Driver]Access denied for user 'root'@'192.168.2.27' (using password: YES) (1045) (SQLDriverConnect)")

I want to receive just the message part of the error i.e.

Access denied for user 'root'@'192.168.2.27'(using password: YES)

I dont know if I can catch errors specifically like, driver not found, host down etc..

I also tried catching errors as:

 except pyodbc.OperationalError, err:
    logging.warn(err)
except pyodbc.DataError, err:
    logging.warn(err)
except pyodbc.IntegrityError, err:
    logging.warn(err)
except pyodbc.ProgrammingError, err:
    logging.warn(err)
except pyodbc.NotSupportedError, err:
    logging.warn(err)
except pyodbc.DatabaseError, err:
    logging.warn(err)
except pyodbc.Error, err:
    logging.warn(err)

but the last one always catches the error.

Fruthermore i saw the pyodbc.Error.message is always empty. How can i get just the message in the error.

Thanks

Answer 1

This worked for me.

    try:
        cnxn = pyodbc.connect(...)
    except pyodbc.Error as ex:
        sqlstate = ex.args[0]
        if sqlstate == '28000':
            print("LDAP Connection failed: check password")

There are different SQLSTATES and you can have if-else statements to print out the cause.

Similarly,

  try:
        cnxn = pyodbc.connect(...)
  except pyodbc.Error as ex:
        sqlstate = ex.args[1]
        print(sqlstate) 

will give you the second part of the error with description. For exampleex.args[0] give you 28000 and ex.args[1] gives [28000] LDAP authentication failed for user 'user' (24) (SQLDriverConnect)

You can then use String manipulation techniques there to just print out what you want. Hope this helps.