json - How to exclude the result of the specified keyword

Question

I would like to specify some keywords from the json result and exclude the result. (For example, in the image, I want to exclude two results of McDonald's of name.) I searched variously, but I do not know how to do it.

Thanks!

json.results

for i in 0...totalHitCount - 1{
    if json["results"][i]["geometry"]["location"]["lat"] != "" &&
    json["results"][i]["geometry"]["location"]["lng"] != "" &&
    json["results"][i]["name"] != "" {
        let extractedExpr = ShopData(lat: json["results"][i]["geometry"]["location"]["lat"].double,lng:json["results"][i]["geometry"]["location"]["lng"].double,name:json["results"][i]["name"].string)
        print(json["results"][i]["name"].string)
        let shopData = extractedExpr
        self.shopDataArray.append(shopData)
        print(self.shopDataArray.debugDescription)
    }

    else{
        print("")
    }

}

Answer 1

To filter some names create a blacklist, the contents can be just parts of the names for example

let blackList = ["McDonald", "Kentucky"]

Then filter for

• lat and long exists

• name exists and is not empty

• blacklist does not contain name

  let results = json["results"].arrayValue
  for result in results {
      let location = result["geometry"]["location"]
      if let lat = location["lat"].double,
          let lng = location["lng"].double,
          let name = result["name"].string, !name.isEmpty,
          !blackList.contains(where: { name.contains($0) }) {
  
          let extractedExpr = ShopData(lat: lat, lng: lng, name: name)
          print(name)
          let shopData = extractedExpr
          self.shopDataArray.append(shopData)
          print(self.shopDataArray.debugDescription)
  
      } else {
          print(result)
      }
  }
  

The code is a bit swiftier and you are strongly encouraged to drop SwiftyJSON in favor of Codable