comparison - How to elegantly compare tuples in Swift?

Question

I do have 2 different tuples of type (Double, Double):

let tuple1: (Double, Double) = (1, 2)
let tuple2: (Double, Double) = (3, 4)

I want to compare their values using a simple if statement. Something like:

if (tuple1 == tuple2) {
    // Do stuff
}

This throws the following error:

Could not find an overload for '==' that accepts the supplied arguments

My current solution is a function like this:

func compareTuples <T: Equatable> (tuple1: (T, T), tuple2: (T, T)) -> Bool {
    return (tuple1.0 == tuple2.0) && (tuple1.1 == tuple2.1)
}

I already tried to write an extension but can't make it work for tuples. Do you have a more elegant solution to this problem?

Answer 1

Update

As Martin R states in the comments, tuples with up to six components can now be compared with ==. Tuples with different component counts or different component types are considered to be different types so these cannot be compared, but the code for the simple case I described below is now obsolete.

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Try this:

func == <T:Equatable> (tuple1:(T,T),tuple2:(T,T)) -> Bool
{
   return (tuple1.0 == tuple2.0) && (tuple1.1 == tuple2.1)
}

It's exactly the same as yours, but I called it ==. Then things like:

(1, 1) == (1, 1)

are true and

(1, 1) == (1, 2)

are false