python - Numpy equivalent of if/else list comprehension

Question

Is there a numpy way of doing

n = [x-t if x > 0 else x for x in nps]

similar to this

n = np.array(a)
n[np.abs(n) < t] = 0

something like this perhaps?

n[n > 0] = n-t

Answer 1

Can't test now, but try

np.where(n > 0, n - t, n)

See documentation