Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
547 views
in Technique[技术] by (71.8m points)

compiler construction - Byte precision pointer arithmetic in C when sizeof(char) != 1

How can one portably perform pointer arithmetic with single byte precision?

Keep in mind that:

  • char is not 1 byte on all platforms
  • sizeof(void) == 1 is only available as an extension in GCC
  • While some platforms may have pointer deref pointer alignment restrictions, arithmetic may still require a finer granularity than the size of the smallest fundamental POD type
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Your assumption is flawed - sizeof(char) is defined to be 1 everywhere.

From the C99 standard (TC3), in section 6.5.3.4 ("The sizeof operator"):

(paragraph 2)

The sizeof operator yields the size (in bytes) of its operand, which may be an expression or the parenthesized name of a type.

(paragraph 3)

When applied to an operand that has type char, unsigned char, or signed char, (or a qualified version thereof) the result is 1.

When these are taken together, it becomes clear that in C, whatever size a char is, that size is a "byte" (even if that's more than 8 bits, on some given platform).

A char is therefore the smallest addressable type. If you need to address in units smaller than a char, your only choice is to read a char at a time and use bitwise operators to mask out the parts of the char that you want.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...