go - How to convert []int8 to string

Question

What's the best way (fastest performance) to convert from []int8 to string?

For []byte we could do string(byteslice), but for []int8 it gives an error:

cannot convert ba (type []int8) to type string

I got the ba from SliceScan() method of *sqlx.Rows that produces []int8 instead of string

Is this solution the fastest?

func B2S(bs []int8) string {
    ba := []byte{}
    for _, b := range bs {
        ba = append(ba, byte(b))
    }
    return string(ba)
}

EDIT my bad, it's uint8 instead of int8.. so I can do string(ba) directly.

Answer 1

Waitting for answers