Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
738 views
in Technique[技术] by (71.8m points)

php - Fatal error: Cannot pass parameter 1 by reference

I have this line:

$stmt->bind_result('d', $keyarray['payment_gross']);

and I get this error:

Fatal error: Cannot pass parameter 1 by reference in /home/star1231/public_html/pdt.php on line 35

What is the problem here?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Not much I can tell about your code, but if parameter 1 is passed by reference in function definition then you need to do this.

$char = 'd';
$stmt->bind_result($char, $keyarray['payment_gross']);

Only variables can be passed by reference since you are passing the address of the variable and not an actual value. Let me know if it solves it


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...