html - Why won't Python display this text correctly? (UTF-8 Decoding Issue)

Question

import urllib.request as u

zipcode = str(47401)
url = 'http://watchdog.net/us/?zip=' + zipcode
con = u.urlopen(url)

page = str(con.read())
value3 = int(page.find("<title>")) + 7
value4 = int(page.find("</title>")) - 15
district = str(page[value3:value4])
print(district)
newdistrict = district.replace("xe2x80x99","'")
print(newdistrict)

For some reason, my code is pulling in the title in the following format: IN-09: Indianaxe2x80x99s 9th. I know the xe string of characters is unicode for the ' symbol, but I can't figure out how to get python to replace that set of characters with the ' symbol. I've tried decoding the string but it's already in unicode and the replace code above doesn't change anything. Any advice as to what I'm doing incorrectly?

Answer 1

When you call con.text(), this returns a bytes object. Calling str() on it returns a string of the representation of it - thus, the escapes are used rather than the real characters, if you don't specify an encoding. (That means that your string ends up containing \xe2\x80\x99 as well as all sorts of other undesired things.) bytes is mostly like str in Python 2: it doesn't have any encoding information stored. str in Python 3 is like unicode in Python 2; it has the encoding. So, when turning a bytes object into a str object, you need to tell it what encoding it is actually in. In this case, that's utf-8.

Instead of calling str() on it, you would be better to use bytes.decode; it's the same thing, just neater.

>>> import urllib.request as u
>>> zipcode = 47401
>>> url = 'http://watchdog.net/us/?zip={}'.format(zipcode)
>>> con = u.urlopen(url)
>>> page = con.read().decode('utf-8')
>>> page[page.find("<title>") + 7:page.find("</title>") - 15]
'IN-09: Indiana’s 9th'

The only functional change that has been made here is the specification to decode the bytes object as 'utf-8'.