bash - use "!" to execute commands with same parameter in a script

Question

In a shell, I run following commands without problem,

ls -al

!ls

the second invocation to ls also list files with -al flag. However, when I put the above script to a bash script, complaints are thrown,

!ls, command not found.

how to realise the same effects in script?

Answer 1

You would need to turn on both command history and !-style history expansion in your script (both are off by default in non-interactive shells):

set -o history
set -o histexpand

The expanded command is also echoed to standard error, just like in an interactive shell. You can prevent that by turning on the histverify shell option (shopt -s histverify), but in a non-interactive shell, that seems to make the history expansion a null-op.