php - call to a member function execute() on a non-object

Question

My script containing that error is this:

$stmt = $this->db->prepare('SELECT libelle,activite,adresse,tel,lat,lng FROM etablissements where type IN ('.$in_list.')');
        $stmt->execute();
        $stmt->bind_result($libelle,$activite,$adresse,$tel,$lat,$lng);

The php version running on the server (not localhost) is 5.2.17

Answer 1

$stmt is supposed to be an object with the method execute().
Seems like $this->db->prepare() is not returning the good result.

If $this->db is a mysqli() object you should bind the parameters like that:

if ($stmt = $this->db->prepare('SELECT libelle,activite,adresse,tel,lat,lng FROM etablissements where type IN (?)')) {
  $stmt->bind_param("s", $in_list);
  $stmt->execute();
  // ...
}