Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
361 views
in Technique[技术] by (71.8m points)

sql - dynamic table name in select statement

I have a series of history tables in an oracle 9 database. History_table_00 contains last months data, History_table_01 contains the month before, and History_table_02 the month before that. Next month, History_table_02 will automatically get renamed to history_table_03, history_table_01 renamed to history_table_02, history_table_00 renamed to history_table_01, and a new history_table_00 will be created to gather the newest history (I really hope I am making sense).

Anyway, I need to write a select statement that will dynamically select all history tables. I am hoping this won't be too complicated because they all share the same name, just appended with sequential number so I can discover the table names with:

select table_name from all_tables where table_name like 'HISTORY_TABLE_%';

My standard query for each table is going to be:

select id, name, data_column_1, data_column_2 from history_table_%;

What do I have to do to accomplish the goal of writing a sql statement that will always select from all history tables without me needing to go in every month and add the new table? Thanks for anything you guys can provide.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

you can use ref cursor but i wouldn't recommend it. it goes like this

create table tab_01 as select 1 a , 10 b from dual;
create table tab_02 as select 2 a , 20 b from dual;
create table tab_03 as select 3 a , 30 b from dual;

create or replace function get_all_history
return sys_refcursor
as
   r sys_refcursor;
   stmt varchar2(32000);
   cursor c_tables is
           select  table_name
           from    user_tables
           where   table_name like 'TAB_%';
begin
   for x in c_tables loop
           stmt := stmt || ' select * from ' || x.table_name ||' union all';
   end loop;
   stmt := substr(stmt , 1 , length(stmt) - length('union all'));
   open r for stmt;
   return r;
end;
/

SQL> select get_all_history() from dual;

GET_ALL_HISTORY()
--------------------
CURSOR STATEMENT : 1

CURSOR STATEMENT : 1

         A          B
---------- ----------
         1         10
         2         20
         3         30

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...