python - Print all even numbers in a list until a given number

Question

I am just beginning to dabble in Python, and have started to go through the chapters on learnpython.org. In the 'Loops' chapter, I have solved the challenge with the following code. However I am not sure it is the most efficient. It certainly doesn't seem to be as I have to define the "number to not go beyond" twice. In this (I'm guessing) easy problem, DRY should be possible to adhere to, right?

The exercise is

Loop through and print out all even numbers from the numbers list in the same order they are received. Don't print any numbers that come after 237 in the sequence.

My code:

numbers = [ 951, 402, 984, 651, 360, 69, 408, 319, 601, 485, 980, 507, 725, 547, 544, 615, 83, 165, 141, 501, 263, 617, 865, 575, 219, 390, 984, 592, 236, 105, 942, 941, 386, 462, 47, 418, 907, 344, 236, 375, 823, 566, 597, 978, 328, 615, 953, 345, 399, 162, 758, 219, 918, 237, 412, 566, 826, 248, 866, 950, 626, 949, 687, 217, 815, 67, 104, 58, 512, 24, 892, 894, 767, 553, 81, 379, 843, 831, 445, 742, 717, 958, 609, 842, 451, 688, 753, 854, 685, 93, 857, 440, 380, 126, 721, 328, 753, 470, 743, 527 ]

# My Solution
for x in numbers:
  if x != 237:
    if x % 2 == 0:
      print x
  if x == 237:
    break

Answer 1

That's what else and elif are for:

for x in numbers:
  if x == 237:
    break
  elif x % 2 == 0:
    print x