python 3.x - How to bookmark a page in Django?

Question

I am trying to edit an html page so a logged in user can favorite / bookmark a video.id

Here is the .html file

<td>
    <form method='POST' action="{% url 'researcher_view_app:favourite_post' video.id %}">
        {% csrf_token %}
        <input type='hidden' name='video' value={{ video.id }}>
        <button type='submit'>Bookmark</button>
    </form>
</td>

Here is the urls.py file

path('<int:fav_id>/favourite_post', views.favourite_post, name='favourite_post'),

Here is the view.py file

def favourite_post(request, fav_id):
    video = get_object_or_404(Video, id=fav_id)
    if request.method == 'POST':
        video.

   return render(request, 'researcher_view_app/%s' % fav_id)

Answer 1

• First you modify the models.py that has the user models

class ProjectUser(AbstractUser):
    images = models.ManyToManyField(Images)

    def __str__(self):
        return self.email

• In the .html file add the following:

{% for image in available_images %}
/* show image */
<form method='post' action="{% url 'user-image-add' %}">
 {% csrf_token %}
 <input type='hidden' name='image' value={{image.id}}>
 <button type='submit'>bookmark</button>
</form>
{% endfor %}

• In your views.py add the following method

def user_image_add(request):
    user_image_form = ImageForm(request.POST or None)
    if request.method == 'POST' and user_image_form.is_valid(): 
         request.user.images.add(user_image_form.cleaned_data['image'])
         return JsonResponse(status=200)
    raise Http404()

• Create a forms.py file in your add and add the following:

class ImageForm(forms.Form):
    image = forms.ModelChoiceField(queryset=Images.objects.all())

To show those bookmarked images you can just iterate over request.user.images (it gives you a QS of Images) similar to code above.

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• In the urls.py add the following:

path('user-image-add/', views.user_image_add, 'user-image-add')

• In models.py add a method in User model for getting bool if video is bookmarked

def is_bookmarked(self, video_id): 
    return self.bookmarked_videos.filter(id=video_id).exists()

simirlarly is_bookmarked can be added to Video model accepting user_id and checking video.projectuser_set.

And add the following to your .html file where users bookmarked a video

`{% if video.is_bookmarked %}`

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• Delete the UserProfile as you do not need it. Just make sure to have needed instance in context of view.