Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
412 views
in Technique[技术] by (71.8m points)

audio - How to find the fundamental frequency of a guitar string sound?

I want to build a guitar tuner app for Iphone. My goal is to find the fundamental frequency of sound generated by a guitar string. I have used bits of code from aurioTouch sample provided by Apple to calculate frequency spectrum and I find the frequency with the highest amplitude . It works fine for pure sounds (the ones that have only one frequency) but for sounds from a guitar string it produces wrong results. I have read that this is because of the overtones generate by the guitar string that might have higher amplitudes than the fundamental one. How can I find the fundamental frequency so it works for guitar strings? Is there an open-source library in C/C++/Obj-C for sound analyzing (or signal processing)?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can use the signal's autocorrelation, which is the inverse transform of the magnitude squared of the DFT. If you're sampling at 44100 samples/s, then a 82.4 Hz fundamental is about 535 samples, whereas 1479.98 Hz is about 30 samples. Look for the peak positive lag in that range (e.g. from 28 to 560). Make sure your window is at least two periods of the longest fundamental, which would be 1070 samples here. To the next power of two that's a 2048-sample buffer. For better frequency resolution and a less biased estimate, use a longer buffer, but not so long that the signal is no longer approximately stationary. Here's an example in Python:

from pylab import *
import wave

fs = 44100.0   # sample rate
K = 3          # number of windows
L = 8192       # 1st pass window overlap, 50%
M = 16384      # 1st pass window length
N = 32768      # 1st pass DFT lenth: acyclic correlation

# load a sample of guitar playing an open string 6
# with a fundamental frequency of 82.4 Hz (in theory),
# but this sample is actually at about 81.97 Hz
g = fromstring(wave.open('dist_gtr_6.wav').readframes(-1),
               dtype='int16')
g = g / float64(max(abs(g)))    # normalize to +/- 1.0
mi = len(g) / 4                 # start index

def welch(x, w, L, N):
    # Welch's method
    M = len(w)
    K = (len(x) - L) / (M - L)
    Xsq = zeros(N/2+1)                  # len(N-point rfft) = N/2+1
    for k in range(K):
        m = k * ( M - L)
        xt = w * x[m:m+M]
        # use rfft for efficiency (assumes x is real-valued)
        Xsq = Xsq + abs(rfft(xt, N)) ** 2
    Xsq = Xsq / K
    Wsq = abs(rfft(w, N)) ** 2
    bias = irfft(Wsq)                   # for unbiasing Rxx and Sxx
    p = dot(x,x) / len(x)               # avg power, used as a check
    return Xsq, bias, p

# first pass: acyclic autocorrelation
x = g[mi:mi + K*M - (K-1)*L]        # len(x) = 32768
w = hamming(M)                      # hamming[m] = 0.54 - 0.46*cos(2*pi*m/M)
                                    # reduces the side lobes in DFT
Xsq, bias, p = welch(x, w, L, N)
Rxx = irfft(Xsq)                    # acyclic autocorrelation
Rxx = Rxx / bias                    # unbias (bias is tapered)
mp = argmax(Rxx[28:561]) + 28       # index of 1st peak in 28 to 560

# 2nd pass: cyclic autocorrelation
N = M = L - (L % mp)                # window an integer number of periods
                                    # shortened to ~8192 for stationarity
x = g[mi:mi+K*M]                    # data for K windows
w = ones(M); L = 0                  # rectangular, non-overlaping
Xsq, bias, p = welch(x, w, L, N)
Rxx = irfft(Xsq)                    # cyclic autocorrelation
Rxx = Rxx / bias                    # unbias (bias is constant)
mp = argmax(Rxx[28:561]) + 28       # index of 1st peak in 28 to 560

Sxx = Xsq / bias[0]
Sxx[1:-1] = 2 * Sxx[1:-1]           # fold the freq axis
Sxx = Sxx / N                       # normalize S for avg power
n0 = N / mp
np = argmax(Sxx[n0-2:n0+3]) + n0-2  # bin of the nearest peak power

# check
print "
Average Power"
print "  p:", p
print "Rxx:", Rxx[0]                # should equal dot product, p
print "Sxx:", sum(Sxx), '
'        # should equal Rxx[0]

figure().subplots_adjust(hspace=0.5)
subplot2grid((2,1), (0,0))
title('Autocorrelation, R$_{xx}$'); xlabel('Lags')
mr = r_[:3 * mp]
plot(Rxx[mr]); plot(mp, Rxx[mp], 'ro')
xticks(mp/2 * r_[1:6])
grid(); axis('tight'); ylim(1.25*min(Rxx), 1.25*max(Rxx))

subplot2grid((2,1), (1,0))
title('Power Spectral Density, S$_{xx}$'); xlabel('Frequency (Hz)')
fr = r_[:5 * np]; f = fs * fr / N; 
vlines(f, 0, Sxx[fr], colors='b', linewidth=2)
xticks((fs * np/N  * r_[1:5]).round(3))
grid(); axis('tight'); ylim(0,1.25*max(Sxx[fr]))
show()

Rxx and Sxx

Output:

Average Power
  p: 0.0410611012542
Rxx: 0.0410611012542
Sxx: 0.0410611012542 

The peak lag is 538, which is 44100/538 = 81.97 Hz. The first-pass acyclic DFT shows the fundamental at bin 61, which is 82.10 +/- 0.67 Hz. The 2nd pass uses a window length of 538*15 = 8070, so the DFT frequencies include the fundamental period and harmonics of the string. This enables an ubiased cyclic autocorrelation for an improved PSD estimate with less harmonic spreading (i.e. the correlation can wrap around the window periodically).

Edit: Updated to use Welch's method to estimate the autocorrelation. Overlapping the windows compensates for the Hamming window. I also calculate the tapered bias of the hamming window to unbias the autocorrelation.

Edit: Added a 2nd pass with cyclic correlation to clean up the power spectral density. This pass uses 3 non-overlapping, rectangular windows length 538*15 = 8070 (short enough to be nearly stationary). The bias for cyclic correlation is a constant, instead of the Hamming window's tapered bias.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...