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javascript - Reactjs - setting inline styles correctly

I am trying to use Reactjs with a kendo splitter. The splitter has a style attribute like

style="height: 100%"

With Reactjs, if I have understood things correctly, this can be implemented using an inline style

var style = {
  height: 100
}

However, I am also using Dustin Getz jsxutil to in an attempt to split things a part a bit more and have independent html fragments. Thus far I have the following html fragment (splitter.html)

<div id="splitter" className="k-content">
  <div id="vertical">
    <div>
      <p>Outer splitter : top pane (resizable and collapsible)</p>
    </div>
    <div id="middlePane">
      {height}
      <div id="horizontal" style={height}>
        <div>
          <p>Inner splitter :: left pane</p>
        </div>
        <div>
          <p>Inner splitter :: center pane</p>
        </div>
        <div>
          <p>Inner splitter :: right pane</p>
        </div>
      </div>
    </div>
  <div>
  <p>Outer splitter : bottom pane (non-resizable, non-collapsible)</p>
</div>

and a splitter.js component which references this html as follows

define(['react', 'external/react/js/jsxutil','text!internal/html/splitter.html'],
  function(React, jsxutil, splitterHtml) {
    'use strict';
    console.log('in app:' + splitterHtml);
    return React.createClass({

      render: function () {
        var scope = {
          height: 100
        };
        console.log('about to render:' + scope.height);

        var dom = jsxutil.exec(splitterHtml, scope);
        console.log('rendered:' + dom);
        return dom;
      }    
    });
  }
)

Now when I run this, I can see the height correctly if I put it as content. However, when it executes as the style properties I am getting an error

The `style` prop expects a mapping from style properties to values, not a string. 

So I obviously haven't quite got it mapped across correctly.

I'd be really grateful if someone could give me a steer on correcting this.

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1 Reply

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by (71.8m points)

You could also try setting style inline without using a variable, like so:

style={{"height" : "100%"}} or,

for multiple attributes: style={{"height" : "100%", "width" : "50%"}}


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