python - How do I use numba on a member function of a class?

Question

I'm using the stable version of Numba 0.30.1.

I can do this:

import numba as nb
@nb.jit("void(f8[:])",nopython=True)                             
def complicated(x):                                  
    for a in x:
        b = a**2.+a**3.

as a test case, and the speedup is enormous. But I don't know how to proceed if I need to speed up a function inside a class.

import numba as nb
def myClass(object):
    def __init__(self):
        self.k = 1
    #@nb.jit(???,nopython=True)                             
    def complicated(self,x):                                  
        for a in x:
            b = a**2.+a**3.+self.k

What numba type do I use for the self object? I need to have this function inside a class since it needs to access a member variable.

Answer 1

I was in a very similar situation and I found a way to use a Numba-JITed function inside of a class.

The trick is to use a static method, since this kind of methods are not called prepending the object instance to the argument list. The downside of not having access to self is that you cannot use variables defined outside of the method. So you have to pass them to the static method from a calling method that has access to self. In my case I did not need to define a wrapper method. I just had to split the method I wanted to JIT compile into two methods.

In the case of your example, the solution would be:

from numba import jit

class MyClass:
    def __init__(self):
        self.k = 1

    def calculation(self):
        k = self.k
        return self.complicated([1,2,3],k)

    @staticmethod
    @jit(nopython=True)                             
    def complicated(x,k):                                  
        for a in x:
            b = a**2 .+ a**3 .+ k