python - How can I get a specific field of a csv file?

Question

I need a way to get a specific item(field) of a CSV. Say I have a CSV with 100 rows and 2 columns (comma seperated). First column emails, second column passwords. For example I want to get the password of the email in row 38. So I need only the item from 2nd column row 38...

Say I have a csv file:

aaaaa@aaa.com,bbbbb
ccccc@ccc.com,ddddd

How can I get only 'ddddd' for example?

I'm new to the language and tried some stuff with the csv module, but I don't get it...

Answer 1

import csv
mycsv = csv.reader(open(myfilepath))
for row in mycsv:
   text = row[1]

Following the comments to the SO question here, a best, more robust code would be:

import csv
with open(myfilepath, 'rb') as f:
    mycsv = csv.reader(f)
    for row in mycsv:
        text = row[1]
        ............

Update: If what the OP actually wants is the last string in the last row of the csv file, there are several aproaches that not necesarily needs csv. For example,

fulltxt = open(mifilepath, 'rb').read()
laststring = fulltxt.split(',')[-1]

This is not good for very big files because you load the complete text in memory but could be ok for small files. Note that laststring could include a newline character so strip it before use.

And finally if what the OP wants is the second string in line n (for n=2):

Update 2: This is now the same code than the one in the answer from J.F.Sebastian. (The credit is for him):

import csv
line_number = 2     
with open(myfilepath, 'rb') as f:
    mycsv = csv.reader(f)
    mycsv = list(mycsv)
    text = mycsv[line_number][1]
    ............