python - Django dynamically get view url and check if its the current page

Question

Consider this basic menu:

<ul class="nav navbar-nav">
  <li class="active"><a href="{% url 'home' %}">Home</a></li>
  <li><a href="{% url 'about' %}">About</a></li>
</ul>

I'm trying to give the current page's link an active class, and I want to do this dynamically based on current url and the view's url. So that when a user visits the about page, that page now has the active class and the homepage does not.

I'd like to logic to work like this inside of the <li></li> tags:

{% if request.get_full_path = "{% url 'home' %}" %}class="active"{% endif %}
{% if request.get_full_path = "{% url 'about' %}" %}class="active"{% endif %}

but clearly I cant have two {% ... %} nested inside of each other.

Any ideas on how to get around nesting the two?

Answer 1

I usually use template inheritance in my navigation, in a similar way to the answer alecxe linked to. However, it is possible to compare the use the current URL in an if tag, as you are trying to do.

The url tag allows you to save the result to a variable. You can then use that variable in your if tag.

{% url 'home' as home_url %}
<a href="{{ home_url }}" {% if request.get_full_path == home_url %}class="active"{% endif %}>Home</a>