Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
474 views
in Technique[技术] by (71.8m points)

gcc - Using BX in Thumb code to call a Thumb function, or to jump to a Thumb instruction in another function

I'm trying to learn skills useful in firmware modding (for which i don't have source code) These questions concern use of BX from thumb code to jump or call other existing thumb code.

  1. How do i use BX to JUMP to existing firmware THUMB code, from my THUMB code.
  2. How do i use BX to CALL an existing THUMB function (must set LR first), from my THUMB code.

My understanding is that cpu looks at lsb bit (bit 0) and i have to make sure this is set to 1 in order to keep cpu state to "thumb state". So I guess i have to ADD 1, to set lsb bit to 1.

So ...say i want to just JUMP to 0x24000 ( in the middle of some existing THUMB code)

LDR R6, =0x24000
ADD R6, #1       @ (set lsb to 1)
BX R6

I think this is correct ?

Now say i want to CALL an existing thumb function, using BX, and i want it to return to me, so i need to set LR to where i want it to return.

Lets say the function i want to call is at 0x24000 It was suggested to me to use:

ldr r2, =0x24000
mov lr, pc
bx r2

Here comes what i don't understand:

  1. the address in R2 doesn't have lsb bit set... so won't bx r2 switch mode to ARM mode??

  2. The LR.. The PC has the address of (begining of current instruction, + 4), i was told. In both Thumb and Arm, any instruction address has to be aligned (16 bit or 32 bit), so it won't have the LSB bit set to 1. Only odd numbers have lsb bit set to 1.

So in the code above, i'm setting LR to (PC), an address that DOESN'T have lsb bit 1 set either. So when the function i called comes to it's epilogue, and does BX LR, ... uhmmm.. how can that work to return to my THUMB code ? I must be missing something...

Normally BL is used to call functions. The manual says BL instruction sets the LR to the next line of code... So does this mean that a (normally used) BL THUMB instruction, sets the LR to return addr + 1 automatically?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Wow, thanks for calling me out on this one. I know I tried the qemu code in http://github.com/dwelch67/yagbat and thought XPUT32 which calls PUT32 in the way you describe, and it worked. But it DOES NOT appear to work. I created a number of experiments and am quite surprised, this is not what I was expecting. Now I see why the gnu linker does what it does. Sorry this is a long response but I think it very valuable. It is a confusing topic, I know I have had it wrong for years thinking the pc drags the mode bit around, but it doesn't.

Before I start with the experiments below, if you are going to do this:

LDR R6, =0x24000
ADD R6, #1       @ (set lsb to 1)
BX R6

because you happen to know that 0x24000 is thumb code, just do this instead:

LDR R6, =0x24001
BX R6

And yes, that is how you branch to thumb code from arm or thumb if you happen to know that that hardcoded address 0x24000 is a thumb instruction you bx with a register containing the address plus one.

If you don't know the address but know the name of the address:

ldr r6,=something
bx r6

The nice thing about that is that something can be an arm or thumb address and the above code just works. Well it works if the linker properly knows what type of label that is arm or thumb, if that gets messed up it won't work right as you can see here:

.thumb
ping:
    ldr r0,=pong
    bx r0
.code 32
pong:
    ldr r0,=ping
    bx r0


d6008148 <ping>:
d6008148:   4803        ldr r0, [pc, #12]   ; (d6008158 <pong+0xc>)
d600814a:   4700        bx  r0

d600814c <pong>:
d600814c:   e59f0008    ldr r0, [pc, #8]    ; d600815c <pong+0x10>
d6008150:   e12fff10    bx  r0

d6008158:   d600814c    strle   r8, [r0], -ip, asr #2
d600815c:   d6008148    strle   r8, [r0], -r8, asr #2

That didn't work pong wanted to pull a thumb address from 0xD600815C but got an arm address.

This is all gnu assembler stuff btw, for other tools you may have to do something else. For gas you need to put .thumb_func before a label that you want declared as a thumb label (the term func implying function is misleading, don't worry about what .thumb_func means it just is an assembler/linker game).

.thumb
.thumb_func
ping:
    ldr r0,=pong
    bx r0
.code 32
pong:
    ldr r0,=ping
    bx r0

and now we get what we wanted:

d6008148 <ping>:
d6008148:   4803        ldr r0, [pc, #12]   ; (d6008158 <pong+0xc>)
d600814a:   4700        bx  r0

d600814c <pong>:
d600814c:   e59f0008    ldr r0, [pc, #8]    ; d600815c <pong+0x10>
d6008150:   e12fff10    bx  r0

d6008158:   d600814c    strle   r8, [r0], -ip, asr #2
d600815c:   d6008149    strle   r8, [r0], -r9, asr #2

0xD600815C has that lsbit set so that you don't have to do any work. The compiler takes care of all of this when you are doing calls to C functions for example. For assembler though you have to use that .thumb_func (or some other directive if there is one) to get gas to know this is a thumb label and set the lsbit for you.

So the experiment below was done on an mpcore which is an ARM11 but I also tried testthumb functions 1 through 4 on an ARM7TDMI and qemu with the same results.

.globl testarm
testarm:
    mov r0,pc
    bx lr

armbounce:
    mov r0,lr
    bx lr

.thumb
.thumb_func
.globl testthumb1
testthumb1:
    mov r0,pc
    bx lr
    nop
    nop
    nop
bounce:
    bx lr
.thumb_func
.globl testthumb2
testthumb2:
    mov r2,lr
    mov r0,pc
    bl bounce
    bx r2
    nop
    nop
    nop
.thumb_func
.globl testthumb3
testthumb3:
    mov r2,lr
    mov lr,pc
    mov r0,lr
    bx r2
    nop
    nop
    nop
.thumb_func
.globl testthumb4
testthumb4:
    push {lr}
    ldr r2,=armbounce
    mov r1,pc  ;@ -4
    add r1,#5  ;@ -2
    mov lr,r1  ;@ +0
    bx r2      ;@ +2
    pop {r2}   ;@ +4
    bx r2
.thumb_func
.globl testthumb5
testthumb5:
    push {lr}
    ldr r2,=armbounce
    mov lr,pc
    bx r2
    pop {r2}
    bx r2
.thumb_func
.globl testthumb6
testthumb6:
    push {lr}
    bl testthumb6a
.thumb_func
testthumb6a:
    mov r0,lr
    pop {r2}
    bx r2

.thumb_func
.globl testthumb7
testthumb7:
    push {lr}
    bl armbounce_thumb
    pop {r2}
    bx r2

.thumb_func
.globl testthumb8
testthumb8:
    push {lr}
    bl armbounce_thumb_two
    pop {r2}
    bx r2

.align 4
armbounce_thumb:
    ldr r1,[pc]
    bx r1
.word armbounce

nop
.align 4
armbounce_thumb_two:
    bx pc
    nop
.code 32
    b armbounce

Which becomes:

d60080b4 <testarm>:
d60080b4:   e1a0000f    mov r0, pc
d60080b8:   e12fff1e    bx  lr

d60080bc <armbounce>:
d60080bc:   e1a0000e    mov r0, lr
d60080c0:   e12fff1e    bx  lr

d60080c4 <testthumb1>:
d60080c4:   4678        mov r0, pc
d60080c6:   4770        bx  lr
d60080c8:   46c0        nop         ; (mov r8, r8)
d60080ca:   46c0        nop         ; (mov r8, r8)
d60080cc:   46c0        nop         ; (mov r8, r8)

d60080ce <bounce>:
d60080ce:   4770        bx  lr

d60080d0 <testthumb2>:
d60080d0:   4672        mov r2, lr
d60080d2:   4678        mov r0, pc
d60080d4:   f7ff fffb   bl  d60080ce <bounce>
d60080d8:   4710        bx  r2
d60080da:   46c0        nop         ; (mov r8, r8)
d60080dc:   46c0        nop         ; (mov r8, r8)
d60080de:   46c0        nop         ; (mov r8, r8)

d60080e0 <testthumb3>:
d60080e0:   4672        mov r2, lr
d60080e2:   46fe        mov lr, pc
d60080e4:   4670        mov r0, lr
d60080e6:   4710        bx  r2
d60080e8:   46c0        nop         ; (mov r8, r8)
d60080ea:   46c0        nop         ; (mov r8, r8)
d60080ec:   46c0        nop         ; (mov r8, r8)

d60080ee <testthumb4>:
d60080ee:   b500        push    {lr}
d60080f0:   4a15        ldr r2, [pc, #84]   ; (d6008148 <armbounce_thumb_two+0x8>)
d60080f2:   4679        mov r1, pc
d60080f4:   3105        adds    r1, #5
d60080f6:   468e        mov lr, r1
d60080f8:   4710        bx  r2
d60080fa:   bc04        pop {r2}
d60080fc:   4710        bx  r2

d60080fe <testthumb5>:
d60080fe:   b500        push    {lr}
d6008100:   4a11        ldr r2, [pc, #68]   ; (d6008148 <armbounce_thumb_two+0x8>)
d6008102:   46fe        mov lr, pc
d6008104:   4710        bx  r2
d6008106:   bc04        pop {r2}
d6008108:   4710        bx  r2

d600810a <testthumb6>:
d600810a:   b500        push    {lr}
d600810c:   f000 f800   bl  d6008110 <testthumb6a>

d6008110 <testthumb6a>:
d6008110:   4670        mov r0, lr
d6008112:   bc04        pop {r2}
d6008114:   4710        bx  r2

d6008116 <testthumb7>:
d6008116:   b500        push    {lr}
d6008118:   f000 f80a   bl  d6008130 <armbounce_thumb>
d600811c:   bc04        pop {r2}
d600811e:   4710        bx  r2

d6008120 <testthumb8>:
d6008120:   b500        push    {lr}
d6008122:   f000 f80d   bl  d6008140 <armbounce_thumb_two>
d6008126:   bc04        pop {r2}
d6008128:   4710        bx  r2
d600812a:   46c0        nop         ; (mov r8, r8)
d600812c:   46c0        nop         ; (mov r8, r8)
d600812e:   46c0        nop         ; (mov r8, r8)

d6008130 <armbounce_thumb>:
d6008130:   4900        ldr r1, [pc, #0]    ; (d6008134 <armbounce_thumb+0x4>)
d6008132:   4708        bx  r1
d6008134:   d60080bc            ; <UNDEFINED> instruction: 0xd60080bc
d6008138:   46c0        nop         ; (mov r8, r8)
d600813a:   46c0        nop         ; (mov r8, r8)
d600813c:   46c0        nop         ; (mov r8, r8)
d600813e:   46c0        nop         ; (mov r8, r8)

d6008140 <armbounce_thumb_two>:
d6008140:   4778        bx  pc
d6008142:   46c0        nop         ; (mov r8, r8)
d6008144:   eaffffdc    b   d60080bc <armbounce>
d6008148:   d60080bc            ; <UNDEFINED> instruction: 0xd60080bc
d600814c:   e1a00000    nop         ; (mov r0, r0)

And the results of calling and printing all of these functions:

D60080BC testarm
D60080C8 testthumb1
D60080D6 testthumb2
D60080E6 testthumb3
D60080FB testthumb4
         testthumb5 crashes
D6008111 testthumb6
D600811D testthumb7
D6008127 testthumb8

So what is all of this doing and what does it have to do with your question. This has to do with mixed mode calling from thumb mode (and also from arm which is simpler)

I have been programming ARM and thumb mode at this level for many years, and somehow have had this wrong all along. I thought the program counter always held the mode in that lsbit, I know as you know that you want to have it set or not set when you do a bx instruction.

Very early in the CPU description of the ARM processor in the ARM Architectural Reference Manual (if you are writing assembler you should already have this, if not maybe most of your questions will be answered).

Program counter Register 15 is the Program Counter (PC). It can be used in most
      instructions as a pointer to the instruction which is two instructions after 
      the instruction being executed...

So let's check and see what that really means, does that mean in arm mode two instructions, 8 bytes ahead? And in thumb mode, two instructions ahead, or 4 bytes ahead?

So testarm verifies that the program counter is 8 bytes ahead. Which is also two instructions.

testthumb1 verifies that the program is 4 bytes ahead, which in this case is also two instructions.

testthumb2:

d60080d2:   4678        mov r0, pc
d60080d4:   f7ff fffb   bl  d60080ce <bounce>
d60080d8:   4710        bx  r2

If the program counter was two "instructions" ahead we would get 0xD60080D8 but we instead get 0xD60080D6 which is four bytes ahead, and that makes a lot more sense. Arm mode 8 bytes ahead, thumb mode 4 bytes ahead, no messing with decoding instructions (or data) that are ahead of the code being executed, just add 4 or 8.

testthumb3 was a hope that mov lr,pc was special, it isn't.

If you don't see the pattern yet, the lsbit of the program counter is NOT set, and I guess this makes sense for branch tables for example. So mov lr,pc in thumb mode does NOT set up the link register right for a return.

testthumb4 in a very painful way does take the program counter wherever this code happens to end up and based on carefully placed instructions, computes the return address, if you change that instruction sequence between mov r1,pc and bx r2 you have to return the add. Now why couldn't we just do something like this:

add r1,pc,#1
bx r2

With thumb instructions you can't, with thumb2 you probably could. And there appear to be some processors (armv7) that support both arm instructions and thumb/thumb2 so you might be in a situation where you would want to do that. But you wouldn't add #1 because a thumb2 add instruction, if there is one that allows upper registers and has three operands would be a 4 byte thumb 2 instruction. (you would need to add #3).

So testthumb5 is directly from the code I showed you that lead to part of this question, and it crashes. This is not how


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...