Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
147 views
in Technique[技术] by (71.8m points)

pipeline - "Piping" output from one function to another using Python infix syntax

I'm trying to replicate, roughly, the dplyr package from R using Python/Pandas (as a learning exercise). Something I'm stuck on is the "piping" functionality.

In R/dplyr, this is done using the pipe-operator %>%, where x %>% f(y) is equivalent to f(x, y). If possible, I would like to replicate this using infix syntax (see here).

To illustrate, consider the two functions below.

import pandas as pd

def select(df, *args):
    cols = [x for x in args]
    df = df[cols]
    return df

def rename(df, **kwargs):
    for name, value in kwargs.items():
        df = df.rename(columns={'%s' % name: '%s' % value})
    return df

The first function takes a dataframe and returns only the given columns. The second takes a dataframe, and renames the given columns. For example:

d = {'one' : [1., 2., 3., 4., 4.],
     'two' : [4., 3., 2., 1., 3.]}

df = pd.DataFrame(d)

# Keep only the 'one' column.
df = select(df, 'one')

# Rename the 'one' column to 'new_one'.
df = rename(df, one = 'new_one')

To achieve the same using pipe/infix syntax, the code would be:

df = df | select('one') 
        | rename(one = 'new_one')

So the output from the left-hand side of | gets passed as the first argument to the function on the right-hand side. Whenever I see something like this done (here, for example) it involves lambda functions. Is it possible to pipe a Pandas' dataframe between functions in the same manner?

I know Pandas has the .pipe method, but what's important to me is the syntax of the example I provided. Any help would be appreciated.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

It is hard to implement this using the bitwise or operator because pandas.DataFrame implements it. If you don't mind replacing | with >>, you can try this:

import pandas as pd

def select(df, *args):
    cols = [x for x in args]
    return df[cols]


def rename(df, **kwargs):
    for name, value in kwargs.items():
        df = df.rename(columns={'%s' % name: '%s' % value})
    return df


class SinkInto(object):
    def __init__(self, function, *args, **kwargs):
        self.args = args
        self.kwargs = kwargs
        self.function = function

    def __rrshift__(self, other):
        return self.function(other, *self.args, **self.kwargs)

    def __repr__(self):
        return "<SinkInto {} args={} kwargs={}>".format(
            self.function, 
            self.args, 
            self.kwargs
        )

df = pd.DataFrame({'one' : [1., 2., 3., 4., 4.],
                   'two' : [4., 3., 2., 1., 3.]})

Then you can do:

>>> df
   one  two
0    1    4
1    2    3
2    3    2
3    4    1
4    4    3

>>> df = df >> SinkInto(select, 'one') 
            >> SinkInto(rename, one='new_one')
>>> df
   new_one
0        1
1        2
2        3
3        4
4        4

In Python 3 you can abuse unicode:

>>> print('u01c1')
∥
>>> ∥ = SinkInto
>>> df >> ∥(select, 'one') >> ∥(rename, one='new_one')
   new_one
0        1
1        2
2        3
3        4
4        4

[update]

Thanks for your response. Would it be possible to make a separate class (like SinkInto) for each function to avoid having to pass the functions as an argument?

How about a decorator?

def pipe(original):
    class PipeInto(object):
        data = {'function': original}

        def __init__(self, *args, **kwargs):
            self.data['args'] = args
            self.data['kwargs'] = kwargs

        def __rrshift__(self, other):
            return self.data['function'](
                other, 
                *self.data['args'], 
                **self.data['kwargs']
            )

    return PipeInto


@pipe
def select(df, *args):
    cols = [x for x in args]
    return df[cols]


@pipe
def rename(df, **kwargs):
    for name, value in kwargs.items():
        df = df.rename(columns={'%s' % name: '%s' % value})
    return df

Now you can decorate any function that takes a DataFrame as the first argument:

>>> df >> select('one') >> rename(one='first')
   first
0      1
1      2
2      3
3      4
4      4

Python is awesome!

I know that languages like Ruby are "so expressive" that it encourages people to write every program as new DSL, but this is kind of frowned upon in Python. Many Pythonists consider operator overloading for a different purpose as a sinful blasphemy.

[update]

User OHLáLá is not impressed:

The problem with this solution is when you are trying to call the function instead of piping. – OHLáLá

You can implement the dunder-call method:

def __call__(self, df):
    return df >> self

And then:

>>> select('one')(df)
   one
0  1.0
1  2.0
2  3.0
3  4.0
4  4.0

Looks like it is not easy to please OHLáLá:

In that case you need to call the object explicitly:
select('one')(df) Is there a way to avoid that? – OHLáLá

Well, I can think of a solution but there is a caveat: your original function must not take a second positional argument that is a pandas dataframe (keyword arguments are ok). Lets add a __new__ method to our PipeInto class inside the docorator that tests if the first argument is a dataframe, and if it is then we just call the original function with the arguments:

def __new__(cls, *args, **kwargs):
    if args and isinstance(args[0], pd.DataFrame):
        return cls.data['function'](*args, **kwargs)
    return super().__new__(cls)

It seems to work but probably there is some downside I was unable to spot.

>>> select(df, 'one')
   one
0  1.0
1  2.0
2  3.0
3  4.0
4  4.0

>>> df >> select('one')
   one
0  1.0
1  2.0
2  3.0
3  4.0
4  4.0

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...