I am inexperienced with using C, and I need to use PCRE to get matches.
Here is a sample of my source code:
int test2()
{
const char *error;
int erroffset;
pcre *re;
int rc;
int i;
int ovector[OVECCOUNT];
char *regex = "From:([^@]+)@([^
]+)";
char str[] = "From:regular.expressions@example.com
"
"From:exddd@43434.com
"
"From:7853456@exgem.com
";
re = pcre_compile (
regex, /* the pattern */
0, /* default options */
&error, /* for error message */
&erroffset, /* for error offset */
0); /* use default character tables */
if (!re) {
printf("pcre_compile failed (offset: %d), %s
", erroffset, error);
return -1;
}
rc = pcre_exec (
re, /* the compiled pattern */
0, /* no extra data - pattern was not studied */
str, /* the string to match */
strlen(str), /* the length of the string */
0, /* start at offset 0 in the subject */
0, /* default options */
ovector, /* output vector for substring information */
OVECCOUNT); /* number of elements in the output vector */
if (rc < 0) {
switch (rc) {
case PCRE_ERROR_NOMATCH:
printf("String didn't match");
break;
default:
printf("Error while matching: %d
", rc);
break;
}
free(re);
return -1;
}
for (i = 0; i < rc; i++) {
printf("%2d: %.*s
", i, ovector[2*i+1] - ovector[2*i], str + ovector[2*i]);
}
}
In this demo, the output is only:
0: From:regular.expressions@example.com
1: regular.expressions
2: example.com
I want to output all of the matches; how can I do that?
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…