Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
423 views
in Technique[技术] by (71.8m points)

php - Laravel active menu item for url included parameters

I'm trying to set active class in my list item, but it doesn't work.

My code in blade:

@foreach($data as $site)
  <ul class="sidebar-menu" id="second-menu">
  @if(isAdmin())<li class="{{-- active class  for url parameter --}}"><a href="{{ url('sites/'.$site->id.'/edit') }}" >{{ $site->name }}</a></li>
@endif
</ul>
@endforeach

So, if I write: li class="@if(getRouteName() == 'site@index'){{ 'active' }}@endif" , it works nice, but in my case the problem is that I want to get 'active' class in foreach sites/'.$site->id.'/edit

Many thanks.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use is() method. For example:

<li class="{{ request()->is('sites/*/edit') ? 'active' : '' }}"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...