Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
537 views
in Technique[技术] by (71.8m points)

cordova - want to upload a pic to the server using phonegap in android

I am doing project in android phonegap and I want to upload pic to the server.

But I am not getting idea, where should I put this code.

I can't show any buttons to upload photos, please help.

I am new in this. I refereed this code from phonegap documentation.

I am trying this for hours, but can't get the better solution.

It's my first android phonegap project.

Code:

   <head>
   <script type="text/javascript" charset="utf-8" src="cordova-2.4.0.js"></script>
   <script type="text/javascript" charset="utf-8">        
    document.addEventListener("deviceready", onDeviceReady, false);

    function onDeviceReady() {           
        navigator.camera.getPicture(uploadPhoto,
                function(message) { alert('get picture failed'); },
              { quality: 50, destinationType:    navigator.camera.DestinationType.FILE_URI,
                sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
             );
    }
    function uploadPhoto(imageURI) {
        var options = new FileUploadOptions();
        options.fileKey="file";
        options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
        options.mimeType="image/jpeg";

        var params = {};
        params.value1 = "test";
        params.value2 = "param";

        options.params = params;

        var ft = new FileTransfer();
        ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
    }

    function win(r) {
        console.log("Code = " + r.responseCode);
        console.log("Response = " + r.response);
        console.log("Sent = " + r.bytesSent);
    }

    function fail(error) {
        alert("An error has occurred: Code = " + error.code);
        console.log("upload error source " + error.source);
        console.log("upload error target " + error.target);
    }

    </script>
 </head>
 <body>
    <h1>Example</h1>
    <p>Upload File</p>
 </body>
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You solve your problem using the next code:

<script type="text/javascript">  
function uploadFromGallery() {

    // Retrieve image file location from specified source
    navigator.camera.getPicture(uploadPhoto,
                                function(message) { alert('get picture failed'); },
                                { quality: 50, 
                                destinationType: navigator.camera.DestinationType.FILE_URI,
                                sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
                                );

}

function uploadPhoto(imageURI) {
    var options = new FileUploadOptions();
    options.fileKey="file";
    options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1)+'.png';
    options.mimeType="text/plain";

    var params = new Object();

    options.params = params;

    var ft = new FileTransfer();
    ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
}

function win(r) {
    console.log("Code = " + r.responseCode);
    console.log("Response = " + r.response);
    console.log("Sent = " + r.bytesSent);
}

function fail(error) {
    alert("An error has occurred: Code = " + error.code);
    console.log("upload error source " + error.source);
    console.log("upload error target " + error.target);
}
</script>
</head>
<body>
   <a data-role="button" onClick="uploadFromGallery();">Upload from Gallery</a> 
</body>

See more info on this post: https://stackoverflow.com/a/13862151/1853864


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...