Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
252 views
in Technique[技术] by (71.8m points)

javascript - How to store data of a functional chain?

A simple function below:

const L = a => L;

forms

L
L(1)
L(1)(2)
...

This seems to form a list but the actual data is not stored at all, so if it's required to store the data such as [1,2], what is the smartest practice to have the task done?

const L = (a) => {
 // do somthing
  return L;
};

I would prefer this concise arrow function style, and do not want to destroy the outer structure as much as possible. Surely, I understand some outer structure modification is required, but I am curious what is possible especially in functional style not OO.

The specification is simply to store data of the function chain.

Any ideas? Thanks.

An initial simplest approach would be:

const L = (a) => {
  L.val = a;
  return L;
};
L.val = L;

can do some, but no data accumulation.

{ [Function: L] val: [Circular] }
{ [Function: L] val: 1 }
{ [Function: L] val: 2 }

Notice:

Every list should be independent for the accumulation.

L(3)(4)

will return [3,4] not [2,3,3,4] with prior accumulation of another lists.

Advanced topic!

How to store data of a functional chain of Monoidal List?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Function currying and variadic arguments don't really work together. It's a restriction made obvious once you realize that the following two expressions are incompatible

L (1)     -> [ 1 ]
L (1) (2) -> [ 1, 2 ]

Above L (1) returns a list, but in the second expression we expect L (1) to be a function that we can apply to 2. L (1) can be a list or it can be a function that produces a list; it cannot be both at the same time.

This is why others have proposed things like .list to get the actual value out. You can do that but know that using object properties or relying upon mutation is not necessary. You can use any signal of your choosing

const L = (x, acc = []) =>
  x === undefined
    ? acc
    : y => L (y, [...acc, x])
    
console.log
  ( L ()              // []
  , L (1) ()          // [ 1 ]
  , L (1) (2) ()      // [ 1, 2 ]
  , L (1) (2) (3) ()  // [ 1, 2, 3 ]
  )

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...