Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
459 views
in Technique[技术] by (71.8m points)

html - How to Create a Dynamic Drop Down List in PHP populated from MySQL Database

I am trying to create a dynamic drop down list using PHP and mysql database. I have written the following code and its giving me the output, but the problem is that its showing different drop-down menu for each item, I want all items in a single drop down list. Kindly check it and guide me.

        $select_query=          "Select name from category";
        $select_query_run =     mysql_query($select_query);
        while   ($select_query_array=   mysql_fetch_array($select_query_run) )
        {
            foreach ($select_query_array as $select_query_display)
            {
                echo "  
                    <select>
                        <option value='' >$select_query_display</option>                        
                    </select>
                ";


                }

            }

Thanks

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Get rid of the inner foreach loop... it is doing nothing for you and move the start and end select tags outside of the while loop.

$select_query=          "Select name from category";
$select_query_run =     mysql_query($select_query);
echo "<select name='category'>";
while ($select_query_array=   mysql_fetch_array($select_query_run) )
{
   echo "<option value='' >".htmlspecialchars($select_query_array["name"])."</option>";
}
echo "</select>";

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...