python - Weird function return value?

Question

I am trying to remove everything between curly braces in a string, and trying to do that recursivesly. And I am returning x here when the recursion is over, but somehow the function doit is returning None here. Though printing x within the def prints the correct string. What am I doing wrong?

strs = "i am a string but i've some {text in brackets} braces, and here are some more {i am the second one} braces"
def doit(x,ind=0):
   if x.find('{',ind)!=-1 and x.find('}',ind)!=-1:
     start=x.find('{',ind)
     end=x.find('}',ind)
     y=x[start:end+1]
     x=x[:start]+x[end+1:]
     #print(x)
     doit(x,end+1)
   else:
       return x

print(doit(strs))

output:
None

Answer 1

You never return anything if the if block succeeds. The return statement lies in the else block, and is only executed if everything else isn't. You want to return the value you get from the recursion.

if x.find('{', ind) != -1 and x.find('}', ind) != -1:
    ...
    return doit(x, end+1)
else:
    return x