ios - How to get file path in iPhone app

Question

I have a problem accessing my files in my app.

I am currently using

//Directly from TileMap example from WWDC2010
NSString *tileDirectory = [[[NSBundle mainBundle] resourcePath] 
                           stringByAppendingPathComponent:@"Tiles"];

to access my tiles for my MKOverlay. This gives me this directory

/Users/xxxx/Library/Application Support/iPhone Simulator/4.2/Applications/9D62025C-C53B-472C-8309-xxxx/xxxx.app/Tiles

The x's is only for privacy reasons

I have my tiles in a folder called Tiles in the root of my application which is in Xcode in a group called Tiles which is in directly in the Resources group.

When I run my app, I get a simple error saying that it could not find my tiles at the generated directory (the one quote above) If I replace that piece of code and make it:

NSString *tileDirectory = @"/Users/xxxx/Documents/xxxx/Tiles";

Then my app works fine. This is obviously because it finds my tiles in its direct location on my Mac. This is fine for testing, but I need it to work on my iPhone/iPad.

This problem might be occurring due to:

• The generated directory is incorrect.
• The tile images aren't getting included in the builded .app file.

Either way, I have no clue of what to do to solve it.

How can I solve this problem?

---

[EDIT]

I changed that piece of code to:

NSString *tileDirectory = [[NSBundle mainBundle] resourcePath];

Now it works in simulator, because all files are in the apps root folder and I don't ask for it to enter another directory called "Tiles".

This runs with no error on the simulator, but when on my iPhone it gives the original error (just a different file path but also ending with /xxxx.app

How can I ensure a directory in my app file such as xxxx.app/Tiles - TileMap does this.

Answer 1

Since it is your files in your app bundle, I think you can use pathForResource:ofType: to get the full pathname of your file.

Here is an example:

NSString* filePath = [[NSBundle mainBundle] pathForResource:@"your_file_name" 
                                            ofType:@"the_file_extension"];