ios - DispatchQueue crashing with main.sync in Swift

Question

Please explain to me why I am getting this crash?

Thread 1: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0)

in this

DispatchQueue.main.sync { print("sync") }

This is my code.

    override func viewDidLoad() {
    super.viewDidLoad()


    print("Start")
    DispatchQueue.main.async {
        print("async")

    }
    DispatchQueue.main.sync {
        print("sync")
    }
    print("Finish")
}

Answer 1

NEVER call the sync function on the main queue

If you call the sync function on the main queue it will block the queue as well as the queue will be waiting for the task to be completed but the task will never be finished since it will not be even able to start due to the queue is already blocked. It is called deadlock.

Two (or sometimes more) items — in most cases, threads — are said to be deadlocked if they all get stuck waiting for each other to complete or perform another action. The first can’t finish because it’s waiting for the second to finish. But the second can’t finish because it’s waiting for the first to finish.

You need to be careful though. Imagine if you call sync and target the current queue you’re already running on. This will result in a deadlock situation.

Use sync to keep track of your work with dispatch barriers, or when you need to wait for the operation to finish before you can use the data processed by the closure.

When to use sync?

When we need to wait until the task is finished. F.e. when we are making sure that some function/method is not double called. F.e. we have synchronization and trying to prevent it to be double called until it's completely finished. When you need to wait for something done on a DIFFERENT queue and only then continue working on your current queue

Synchronous vs. Asynchronous

With GCD, you can dispatch a task either synchronously or asynchronously.

A synchronous function returns control to the caller after the task is completed.

An asynchronous function returns immediately, ordering the task to be done but not waiting for it. Thus, an asynchronous function does not block the current thread of execution from proceeding on to the next function.