Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
989 views
in Technique[技术] by (71.8m points)

php - Return a JSON array from a Controller in Symfony

I am trying return a JSON response from a controller in Symfony 2. Form example, in Spring MVC I can get a JSON response with @ResponseBody annotattion. I want get a JSON response, no mtter if it is a JSON Array or a Json Object, then, manipulate it with javascript in the view.

I try the next code:

/**
     * @Route(
     *      "/drop/getCategory/",
     *      name="getCategory"
     * )
     * @Method("GET")
     */
    public function getAllCategoryAction() {
        $categorias = $this->getDoctrine()
                           ->getRepository('AppBundle:Categoria')
                           ->findAll();

        $response = new JsonResponse();
        $response->setData($categorias);

        $response->headers->set('Content-Type', 'application/json');
        return $response;
    }

But I get [{},{}] as Response in the browser. I try with $response = new Response(json_encode($categorias)); too, but I get the same result.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I think the @darkangelo answer need explainations.

The findAll() method return a collection of objects.

$categorias = $this->getDoctrine()
                   ->getRepository('AppBundle:Categoria')
                   ->findAll();

To build your response, you have to add all getters of your entities to your response like :

$arrayCollection = array();

foreach($categorias as $item) {
     $arrayCollection[] = array(
         'id' => $item->getId(),
         // ... Same for each property you want
     );
}

return new JsonResponse($arrayCollection);

Use QueryBuilder allows you to return results as arrays containing all properties :

$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
    'SELECT c
    FROM AppBundle:Categoria c'
);
$categorias = $query->getArrayResult();

return new JsonResponse($categorias);

The getArrayResult() avoids need of getters.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...