Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
501 views
in Technique[技术] by (71.8m points)

f# - Pipe forwards in C#

Continuing my investigation of expressing F# ideas in C#, I wanted a pipe forward operator. For anything wrapped in a IEnumerable, we already have it, as you can .NextFunc() to your heart's content. But for example if you have any fold-like reduction at the end, you can't feed the result of that into a function.

Here are two extension methods, I wondered if anyone else had tried this, and if it's a good idea or not (EDIT: now with Earwicker's Maybe included):

public static void Pipe<T>(this T val, Action<T> action) where T : class
{ if (val!=null) action(val); }

public static R Pipe<T, R>(this T val, Func<T, R> func) where T : class where R : class
{ return val!=null?func(val):null; }

You can then write something like:

Func<string, string[]> readlines = (f) => File.ReadAllLines(f);
Action<string, string> writefile = (f, s) => File.WriteAllText(f, s);

Action<string, string> RemoveLinesContaining = (file, text) =>
    {
        file.Pipe(readlines)
            .Filter(s => !s.Contains(text))
            .Fold((val, sb) => sb.AppendLine(val), new StringBuilder())
            .Pipe((o) => o.ToString())
            .Pipe((s) => writefile(file, s));
    };

(I know, Filter == Where in C#, and Fold==Aggregate, but I wanted to roll my own, and I could have done WriteAllLines, but that's not the point)

EDIT: corrections as per Earwicker's comment (if I've understood correctly).

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I haven't bothered with a raw pipe, but I have tried making all references into the Maybe monad:

public static class ReferenceExtensions
{
    public static TOut IfNotNull<TIn, TOut>(this TIn v, Func<TIn, TOut> f)
                                    where TIn : class 
                                    where TOut: class
    {
        if (v == null)
            return null;

        return f(v);
    }
}

Then suppose you have an object model that lets you lookup a RecordCompany by name, and then lookup a Band within that RecordCompany, a Member of the Band, and any of these might return null, so this might throw a NullReferenceException:

var pixiesDrummer = Music.GetCompany("4ad.com")
                         .GetBand("Pixes")
                         .GetMember("David");

We can fix that:

var pixiesDrummer = Music.GetCompany("4ad.com")
                         .IfNotNull(rc => rc.GetBand("Pixes"))
                         .IfNotNull(band => band.GetMember("David"));

Hey presto, if any of those transitions return null, pixiesDrummer will be null.

Wouldn't it be great if we could do extension methods that are operator overloads?

public static TOut operator| <TIn, TOut>(TIn v, Func<TIn, TOut> f)

Then I could pipe together my transition lambdas like this:

var pixiesDrummer = Music.GetCompany("4ad.com")     
                     | rc => rc.GetBand("Pixes")
                     | band => band.GetMember("David");

Also wouldn't it be great if System.Void was defined as a type and Action was really just Func<..., Void>?

Update: I blogged a little about the theory behind this.

Update 2: An alternative answer to the original question, which is roughly "How would you express the F# pipe-forward operator in C#?"

Pipe-forward is:

let (|>) x f = f x

In other words, it lets you write a function and its first argument in the opposite order: argument followed by function. It's just a syntactic helper that assists with readability, allowing you to make use of infix notation with any function.

This is exactly what extension methods are for in C#. Without them, we would have to write:

var n = Enumerable.Select(numbers, m => m * 2);

With them, we can write:

var n = numbers.Select(m => m * 2);

(Ignore the fact that they also let us omit the class name - that's a bonus but could also be made available for non-extension methods as it is in Java).

So C# already solves the same problem in a different way.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...